§ 1.19

Вычисление пределов с помощью формулы Тейлора

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Задача 1.19.1

Найти предел.

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(1)

lim⁡x→0ln⁡(1+x)−xx2\lim_{x \rightarrow 0} \frac{\ln (1+x)-x}{x^{2}};

(2)

lim⁡x→0sh⁡2x−2sh⁡xx3\lim_{x \rightarrow 0} \frac{\operatorname {sh} 2 x-2 \operatorname {sh} x}{x^{3}};

(3)

lim⁡x→0ex−1−xx2\lim_{x \rightarrow 0} \frac{e^{x}-1-x}{x^{2}};

(4)

lim⁡x→0cos⁡x−1+x2/2x4\lim_{x \rightarrow 0} \frac{\cos x-1+x^{2} / 2}{x^{4}};

(5)

lim⁡x→0ch⁡3x+cos⁡3x−2x4\lim_{x \rightarrow 0} \frac{\operatorname {ch} 3 x+\cos 3 x-2}{x^{4}}

(6)

lim⁡x→0tg⁡x−sin⁡xx3\lim_{x \rightarrow 0} \frac{\operatorname {tg} x-\sin x}{x^{3}};

(7)

lim⁡x→01+x+1+x3−21−x4x\lim_{x \rightarrow 0} \frac{\sqrt{1+x}+\sqrt[3]{1+x}-2 \sqrt[4]{1-x}}{x}

(8)

lim⁡x→0arctg⁡x−arcsin⁡xx2\lim_{x \rightarrow 0} \frac{\operatorname {arctg} x-\arcsin x}{x^{2}}.

Задача 1.19.2

Найти предел.

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(1)

lim⁡x→0tg⁡x−xsin⁡x−x\lim_{x \rightarrow 0} \frac{\operatorname {tg} x-x}{\sin x-x};

(2)

lim⁡x→0arctg⁡x−arcsin⁡xtg⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{\operatorname {arctg} x-\arcsin x}{\operatorname {tg} x-\sin x};

(3)

lim⁡x→02arcsin⁡x−arcsin⁡2xx3\lim_{x \rightarrow 0} \frac{2 \arcsin x-\arcsin 2 x}{x^{3}};

(4)

lim⁡x→01+2x5−11+x4−1−x\lim_{x \rightarrow 0} \frac{\sqrt[5]{1+2 x}-1}{\sqrt[4]{1+x}-\sqrt{1-x}}

(5)

lim⁡x→01+xcos⁡x−1+2xln⁡(1+x)−x\lim_{x \rightarrow 0} \frac{1+x \cos x-\sqrt{1+2 x}}{\ln (1+x)-x};

(6)

lim⁡x→0ex−1+2xln⁡cos⁡x\lim_{x \rightarrow 0} \frac{e^{x}-\sqrt{1+2 x}}{\ln \cos x}

(7)

lim⁡x→03cos⁡x+arcsin⁡x−31+x3ln⁡(1−x2)\lim_{x \rightarrow 0} \frac{3 \cos x+\arcsin x-3 \sqrt[3]{1+x}}{\ln \left(1-x^{2}\right)};

(8)

lim⁡x→01−x23−xctg⁡xxsin⁡x\lim_{x \rightarrow 0} \frac{\sqrt[3]{1-x^{2}}-x \operatorname {ctg} x}{x \sin x}.

Задача 1.19.3

Найти предел.

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(1)

lim⁡x→0(1+x)1/x−ex\lim_{x \rightarrow 0} \frac{(1+x)^{1 / x}-e}{x};

(2)

lim⁡x→0(1+x)x−1x2\lim_{x \rightarrow 0} \frac{(1+x)^{x}-1}{x^{2}};

(3)

lim⁡x→0(1+x)1/x−e(1−x/2)x2\lim_{x \rightarrow 0} \frac{(1+x)^{1 / x}-e(1-x / 2)}{x^{2}};

(4)

lim⁡x→0cos⁡((π/2)cos⁡x)sin⁡(sin⁡2x)\lim_{x \rightarrow 0} \frac{\cos ((\pi / 2) \cos x)}{\sin \left(\sin^{2} x\right)}.

Задача 1.19.4

Найти предел.

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(1)

lim⁡x→0ex−1+3x+9x2/23x3\lim_{x \rightarrow 0} \frac{e^{x}-\sqrt[3]{1+3 x+9 x^{2} / 2}}{x^{3}};

(2)

lim⁡x→0ln⁡(1+x3)−2sin⁡x+2xcos⁡x2arctg⁡x3\lim_{x \rightarrow 0} \frac{\ln \left(1+x^{3}\right)-2 \sin x+2 x \cos x^{2}}{\operatorname {arctg} x^{3}};

(3)

lim⁡x→0x1+sin⁡x−(1/2)ln⁡(1+x2)−xtg⁡3x\lim_{x \rightarrow 0} \frac{x \sqrt{1+\sin x}-(1 / 2) \ln \left(1+x^{2}\right)-x}{\operatorname {tg}^{3} x};

(4)

lim⁡x→0esin⁡x−1+x2−xcos⁡xln⁡3(1−x)\lim_{x \rightarrow 0} \frac{e^{\sin x}-\sqrt{1+x^{2}}-x \cos x}{\ln^{3}(1-x)};

(5)

lim⁡x→0esin⁡xln⁡cos⁡x−(1+4x)1/4+x−3x2/2xsin⁡x2\lim_{x \rightarrow 0} \frac{e^{\sin x \ln \cos x}-(1+4 x)^{1 / 4}+x-3 x^{2} / 2}{x \sin x^{2}}.

Задача 1.19.5

Найти предел.

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(1)

lim⁡x→0earctg⁡x+ln⁡(1−x)−12−4+x3\lim_{x \rightarrow 0} \frac{e^{\operatorname {arctg} x}+\ln (1-x)-1}{2-\sqrt{4+x^{3}}};

(2)

lim⁡x→01+xsin⁡x+ln⁡cos⁡x−x1−x33−1\lim_{x \rightarrow 0} \frac{\sqrt{1+x} \sin x+\ln \cos x-x}{\sqrt[3]{1-x^{3}}-1};

(3)

lim⁡x→01+xsh⁡x+ln⁡cos⁡x−x1−1−x33\lim_{x \rightarrow 0} \frac{\sqrt{1+x} \operatorname {sh} x+\ln \cos x-x}{1-\sqrt[3]{1-x^{3}}};

(4)

lim⁡x→0ln⁡(e2x+sin⁡x)−3arcsin⁡x+5x2/28+x33−2\lim_{x \rightarrow 0} \frac{\ln \left(e^{2 x}+\sin x\right)-3 \arcsin x+5 x^{2} / 2}{\sqrt[3]{8+x^{3}}-2};

(5)

lim⁡x→0ln⁡(1+ln⁡(1+x)/(1+x))−tg⁡(x−2x2)4+x3−2\lim_{x \rightarrow 0} \frac{\ln (1+\ln (1+x) /(1+x))-\operatorname {tg}\left(x-2 x^{2}\right)}{\sqrt{4+x^{3}}-2}.

Задача 1.19.6

Найти предел.

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(1)

lim⁡x→0cos⁡x−1−x2sin⁡x−x\lim_{x \rightarrow 0} \frac{\cos x-\sqrt{1-x^{2}}}{\sin x-x};

(2)

lim⁡x→01+2x3−cos⁡x4tg⁡x−x\lim_{x \rightarrow 0} \frac{\sqrt{1+2 x^{3}}-\cos x^{4}}{\operatorname {tg} x-x};

(3)

lim⁡x→0x1+sin⁡x+ln⁡(1−x)tg⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{x \sqrt{1+\sin x}+\ln (1-x)}{\operatorname {tg} x-\sin x};

(4)

lim⁡x→01−xln⁡(1+x)−x/(x+1)tg⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{\sqrt{1-x} \ln (1+x)-x /(x+1)}{\operatorname {tg} x-\sin x}.

Задача 1.19.7

Найти предел.

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(1)

lim⁡x→0esin⁡x+ln⁡(1−x)−1arcsin⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{e^{\sin x}+\ln (1-x)-1}{\arcsin x-\sin x};

(2)

lim⁡x→01+2tg⁡x−ex+x2arcsin⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{\sqrt{1+2 \operatorname {tg} x}-e^{x}+x^{2}}{\arcsin x-\sin x}

(3)

lim⁡x→0ln⁡(1+x)cos⁡x−etg⁡x+1+2x2x−sin⁡x\lim_{x \rightarrow 0} \frac{\ln (1+x) \cos x-e^{\operatorname {tg} x}+\sqrt{1+2 x^{2}}}{x-\sin x};

(4)

lim⁡x→01−sin⁡x−ln⁡(1−x/2)−1tg⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{\sqrt{1-\sin x}-\ln (1-x / 2)-1}{\operatorname {tg} x-\sin x};

(5)

lim⁡x→0etg⁡x−x−ch⁡xsin⁡x−arctg⁡x\lim_{x \rightarrow 0} \frac{e^{\operatorname {tg} x}-x-\operatorname {ch} x}{\sin x-\operatorname {arctg} x};

(6)

lim⁡x→0esin⁡x+ln⁡(1−sin⁡x)−1tg⁡x−arctg⁡x\lim_{x \rightarrow 0} \frac{e^{\sin x}+\ln (1-\sin x)-1}{\operatorname {tg} x-\operatorname {arctg} x};

(7)

lim⁡x→01+3x3−esin⁡x+3x2/2arcsin⁡x−tg⁡x\lim_{x \rightarrow 0} \frac{\sqrt[3]{1+3 x}-e^{\sin x}+3 x^{2} / 2}{\arcsin x-\operatorname {tg} x};

(8)

lim⁡x→01+3x3ln⁡(1−x)+sin⁡(sin⁡x)+3x2/2tg⁡x−arcsin⁡x\lim_{x \rightarrow 0} \frac{\sqrt[3]{1+3 x} \ln (1-x)+\sin (\sin x)+3 x^{2} / 2}{\operatorname {tg} x-\arcsin x}.

Задача 1.19.8

Найти предел.

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(1)

lim⁡x→0etg⁡x−1+2x−x(x+x2)x−arctg⁡x\lim_{x \rightarrow 0} \frac{e^{\operatorname {tg} x}-\sqrt{1+2 x}-x\left(x+x^{2}\right)}{x-\operatorname {arctg} x};

(2)

lim⁡x→0ln⁡(1+x/2)−1+sin⁡x+1sh⁡x−arctg⁡x\lim_{x \rightarrow 0} \frac{\ln (1+x / 2)-\sqrt{1+\sin x}+1}{\operatorname {sh} x-\operatorname {arctg} x};

(3)

lim⁡x→0etg⁡(x/2)−1+sin⁡x−x2/4arccos⁡x−arcctg⁡x\lim_{x \rightarrow 0} \frac{e^{\operatorname {tg}(x / 2)}-\sqrt{1+\sin x}-x^{2} / 4}{\arccos x-\operatorname {arcctg} x};

(4)

lim⁡x→01+3x+x23+sin⁡ln⁡(1−x)−e−7x2/6x−arctg⁡x\lim_{x \rightarrow 0} \frac{\sqrt[3]{1+3 x+x^{2}}+\sin \ln (1-x)-e^{-7 x^{2} / 6}}{x-\operatorname {arctg} x};

(5)

lim⁡x→01+sh⁡2x−cos⁡x−xtg⁡x−arctg⁡sin⁡x\lim_{x \rightarrow 0} \frac{\sqrt{1+\operatorname {sh} 2 x}-\cos x-x}{\operatorname {tg} x-\operatorname {arctg} \sin x};

(6)

lim⁡x→02−e2x−cos⁡2x+ln⁡(1+x)sin⁡x−arcsin⁡tg⁡x\lim_{x \rightarrow 0} \frac{\sqrt{2-e^{2 x}}-\cos 2 x+\ln (1+x)}{\sin x-\arcsin \operatorname {tg} x}.

Задача 1.19.9

Найти предел.

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(1)

lim⁡x→0xetg⁡x−sin⁡2x−xx+x3−tg⁡x\lim_{x \rightarrow 0} \frac{x e^{\operatorname {tg} x}-\sin^{2} x-x}{x+x^{3}-\operatorname {tg} x};

(2)

lim⁡x→01+x33−xctg⁡x−x2/3xcos⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{\sqrt[3]{1+x^{3}}-x \operatorname {ctg} x-x^{2} / 3}{x \cos x-\sin x};

(3)

lim⁡x→0cos⁡x−1−2x−xx2tg⁡x−e−x3+1\lim_{x \rightarrow 0} \frac{\cos x-\sqrt{1-2 x}-x}{x^{2} \operatorname {tg} x-e^{-x^{3}}+1}

(4)

lim⁡x→0sin⁡x−ln⁡(sin⁡x+1+x2)tg⁡x−xcos⁡2x\lim_{x \rightarrow 0} \frac{\sin x-\ln \left(\sin x+\sqrt{1+x^{2}}\right)}{\operatorname {tg} x-x \cos^{2} x};

(5)

lim⁡x→0eex−1−1/(1−x)ln⁡((1+x)/(1−x))−2sin⁡x\lim_{x \rightarrow 0} \frac{e^{e^{x}-1}-1 /(1-x)}{\ln ((1+x) /(1-x))-2 \sin x};

(6)

lim⁡x→0tg⁡(sin⁡x)−ln⁡(x+1+x23)−x2/6th⁡(x−x3)−x\lim_{x \rightarrow 0} \frac{\operatorname {tg}(\sin x)-\ln \left(x+\sqrt[3]{1+x^{2}}\right)-x^{2} / 6}{\operatorname {th}\left(x-x^{3}\right)-x}.

Задача 1.19.10

Найти предел.

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(1)

lim⁡x→0e2x−ch⁡2x−2xtg⁡2x−2sin⁡x\lim_{x \rightarrow 0} \frac{e^{2 x}-\operatorname {ch} 2 x-2 x}{\operatorname {tg} 2 x-2 \sin x};

(2)

lim⁡x→0ln⁡(1+x−x2/6)−sh⁡x+2x2/3sin⁡2x−2xcos⁡x\lim_{x \rightarrow 0} \frac{\ln \left(1+x-x^{2} / 6\right)-\operatorname {sh} x+2 x^{2} / 3}{\sin 2 x-2 x \cos x};

(3)

lim⁡x→0x2e2x+ln⁡(1−x2)xcos⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{x^{2} e^{2 x}+\ln \left(1-x^{2}\right)}{x \cos x-\sin x};

(4)

lim⁡x→0arcsin⁡x+3cos⁡x−31+x31+ln⁡(1+x)−ex\lim_{x \rightarrow 0} \frac{\arcsin x+3 \cos x-3 \sqrt[3]{1+x}}{1+\ln (1+x)-e^{x}};

(5)

lim⁡x→0x2ex−ln⁡(1+x2)−arcsin⁡x3xsin⁡x−x2\lim_{x \rightarrow 0} \frac{x^{2} e^{x}-\ln \left(1+x^{2}\right)-\arcsin x^{3}}{x \sin x-x^{2}};

(6)

lim⁡x→0e1+tg⁡x−e1+2xsin⁡(x2/7)−(x/3)ln⁡(1−x)\lim_{x \rightarrow 0} \frac{e^{1+\operatorname {tg} x}-e^{\sqrt{1+2 x}}}{\sin \left(x^{2} / 7\right)-(x / 3) \ln (1-x)};

(7)

lim⁡x→0ex−1+2x+2x2x+tg⁡x−sin⁡2x\lim_{x \rightarrow 0} \frac{e^{x}-\sqrt{1+2 x+2 x^{2}}}{x+\operatorname {tg} x-\sin 2 x}

(8)

lim⁡x→0tg⁡sin⁡x−xcos⁡xex+ln⁡(1−x)−1\lim_{x \rightarrow 0} \frac{\operatorname {tg} \sin x-x \cos x}{e^{x}+\ln (1-x)-1}.

Задача 1.19.11

Найти предел.

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(1)

lim⁡x→0ex−x1+x−1sin⁡xch⁡x−sh⁡x\lim_{x \rightarrow 0} \frac{e^{x}-x \sqrt{1+x}-1}{\sin x \operatorname {ch} x-\operatorname {sh} x};

(2)

lim⁡x→0tg⁡x−ln⁡(x+1+x2)sin⁡x−xcos⁡x\lim_{x \rightarrow 0} \frac{\operatorname {tg} x-\ln \left(x+\sqrt{1+x^{2}}\right)}{\sin x-x \cos x};

(3)

lim⁡x→0ex−x2−ln⁡(1+sin⁡x)−1xcos⁡x−sh⁡x\lim_{x \rightarrow 0} \frac{e^{x-x^{2}}-\ln (1+\sin x)-1}{x \cos x-\operatorname {sh} x};

(4)

lim⁡x→02ln⁡cos⁡x+xsh⁡xsin⁡(x2/2)−sh⁡(x2/2)\lim_{x \rightarrow 0} \frac{2 \ln \cos x+x \operatorname {sh} x}{\sin \left(x^{2} / 2\right)-\operatorname {sh}\left(x^{2} / 2\right)}

(5)

lim⁡x→0ex2tg⁡x−xcos⁡sin⁡xln⁡(1+x)−x1−x\lim_{x \rightarrow 0} \frac{e^{x^{2}} \operatorname {tg} x-x \cos \sin x}{\ln (1+x)-x \sqrt{1-x}};

(6)

lim⁡x→0arcsin⁡x−xexx1−x2−tg⁡x\lim_{x \rightarrow 0} \frac{\arcsin x-x e^{x}}{x \sqrt{1-x^{2}}-\operatorname {tg} x}

Задача 1.19.12

Найти предел.

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(1)

lim⁡x→01−2x+etg⁡x−2sin⁡x/x−cos⁡x−x2/3\lim_{x \rightarrow 0} \frac{\sqrt{1-2 x}+e^{\operatorname {tg} x}-2}{\sin x / x-\cos x-x^{2} / 3};

(2)

lim⁡x→0cos⁡x−xln⁡(1+x)+(3/4)tg⁡x2−1xex−arcsin⁡x−x2\lim_{x \rightarrow 0} \frac{\sqrt{\cos x-x \ln (1+x)}+(3 / 4) \operatorname {tg} x^{2}-1}{x e^{x}-\arcsin x-x^{2}};

(3)

lim⁡x→0sh⁡2x+ln⁡(1−sin⁡x)−sin⁡ln⁡(1+x)(1−2x)−1/2−ex−x2\lim_{x \rightarrow 0} \frac{\operatorname {sh} 2 x+\ln (1-\sin x)-\sin \ln (1+x)}{(1-2 x)^{-1 / 2}-e^{x}-x^{2}};

(4)

lim⁡x→0(1−2x)−1/2−(1+2x)−1/2−arctg⁡2xe−x+ln⁡(1+arcsin⁡x)−1\lim_{x \rightarrow 0} \frac{(1-2 x)^{-1 / 2}-(1+2 x)^{-1 / 2}-\operatorname {arctg} 2 x}{e^{-x}+\ln (1+\arcsin x)-1};

(5)

lim⁡x→0ln⁡(esin⁡x+ln⁡(1−x)+x3/3)ln⁡ch⁡x−x2/2\lim_{x \rightarrow 0} \frac{\ln \left(e^{\sin x}+\ln (1-x)+x^{3} / 3\right)}{\ln \operatorname {ch} x-x^{2} / 2};

(6)

lim⁡x→0sin⁡arctg⁡x−tg⁡xesh⁡x−(1+2x)1/2−x2\lim_{x \rightarrow 0} \frac{\sin \operatorname {arctg} x-\operatorname {tg} x}{e^{\operatorname {sh} x}-(1+2 x)^{1 / 2}-x^{2}}.

Задача 1.19.13

Найти предел.

?
(1)

lim⁡x→01+x23−ex3/4ln⁡(1+3x2)−3x2cos⁡x\lim_{x \rightarrow 0} \frac{\sqrt[3]{1+x^{2}}-e^{x^{3} / 4}}{\ln \left(1+3 x^{2}\right)-3 x^{2} \cos x};

(2)

lim⁡x→0ln⁡(1+x2−x)+tg⁡xx(ch⁡x−ex2)\lim_{x \rightarrow 0} \frac{\ln \left(\sqrt{1+x^{2}}-x\right)+\operatorname {tg} x}{x\left(\operatorname {ch} x-e^{x^{2}}\right)};

(3)

lim⁡x→0ln⁡(e+x)3−ex/(3e)+x2/(3e2)xch⁡x−sin⁡x\lim_{x \rightarrow 0} \frac{\sqrt[3]{\ln (e+x)}-e^{x /(3 e)}+x^{2} /\left(3 e^{2}\right)}{x \operatorname {ch} x-\sin x};

(4)

lim⁡x→0esul⁡x−1+x2−arcsin⁡xsh⁡(x−x2)−ln⁡1+2x\lim_{x \rightarrow 0} \frac{e^{\operatorname {sul} x}-\sqrt{1+x^{2}}-\arcsin x}{\operatorname {sh}\left(x-x^{2}\right)-\ln \sqrt{1+2 x}};

(5)

lim⁡x→0ch⁡(2x/(2+x4))+cos⁡(2x/(2−x4))−2ex4/2tg⁡1+x4−tg⁡1−x4\lim_{x \rightarrow 0} \frac{\operatorname {ch}\left(2 x /\left(2+x^{4}\right)\right)+\cos \left(2 x /\left(2-x^{4}\right)\right)-2 e^{x^{4} / 2}}{\operatorname {tg} \sqrt{1+x^{4}}-\operatorname {tg} \sqrt{1-x^{4}}};

(6)

lim⁡x→0e1+cos⁡x−e2+x2+(3e2/2)sin⁡x2ln⁡(1+x2)−(arctg⁡x)2\lim_{x \rightarrow 0} \frac{e^{1+\cos x}-e^{2+x^{2}}+\left(3 e^{2} / 2\right) \sin x^{2}}{\ln \left(1+x^{2}\right)-(\operatorname {arctg} x)^{2}}.

Задача 1.19.14

Найти предел.

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(1)

lim⁡x→0ln⁡(1+sin⁡2x)−2x+2x2x/2+tg⁡(x/2)−arcsin⁡x\lim_{x \rightarrow 0} \frac{\ln (1+\sin 2 x)-2 x+2 x^{2}}{x / 2+\operatorname {tg}(x / 2)-\arcsin x};

(2)

lim⁡x→01+sin⁡x−(1/2)tg⁡x+x2/8−1ex−1+2x−x2\lim_{x \rightarrow 0} \frac{\sqrt{1+\sin x}-(1 / 2) \operatorname {tg} x+x^{2} / 8-1}{e^{x}-\sqrt{1+2 x}-x^{2}};

(3)

lim⁡x→01+2x−etg⁡x+6x3+x2ln⁡(1+x)−arctg⁡x+x2/2\lim_{x \rightarrow 0} \frac{\sqrt{1+2 x}-e^{\operatorname {tg} x}+6 x^{3}+x^{2}}{\ln (1+x)-\operatorname {arctg} x+x^{2} / 2};

(4)

lim⁡x→0ch⁡2x−(1+3x)−1/3−xx2/2+ln⁡(1+tg⁡x)−arcsin⁡x\lim_{x \rightarrow 0} \frac{\operatorname {ch} 2 x-(1+3 x)^{-1 / 3}-x}{x^{2} / 2+\ln (1+\operatorname {tg} x)-\arcsin x};

(5)

lim⁡x→0ex/(1−x)−sh⁡x−cos⁡x1+x6+1−x6−2\lim_{x \rightarrow 0} \frac{e^{x /(1-x)}-\operatorname {sh} x-\cos x}{\sqrt[6]{1+x}+\sqrt[6]{1-x}-2};

(6)

lim⁡x→0x+ch⁡x−earcsin⁡xtg⁡x+1−3x3−2cos⁡x+1\lim_{x \rightarrow 0} \frac{x+\operatorname {ch} x-e^{\arcsin x}}{\operatorname {tg} x+\sqrt[3]{1-3 x}-2 \cos x+1};

(7)

lim⁡x→02x+cos⁡2x−etg⁡x+2x22sin⁡x−2ln⁡(1+x)−x2\lim_{x \rightarrow 0} \frac{\sqrt{2 x+\cos 2 x}-e^{\operatorname {tg} x}+2 x^{2}}{2 \sin x-2 \ln (1+x)-x^{2}},

(8)

lim⁡x→0sh⁡sin⁡x3+sin⁡sh⁡x3(x2/2)1−x+ln⁡(1+x)−xcos⁡x\lim_{x \rightarrow 0} \frac{\operatorname {sh} \sin x^{3}+\sin \operatorname {sh} x^{3}}{\left(x^{2} / 2\right) \sqrt{1-x}+\ln (1+x)-x \cos x}

Задача 1.19.15

Найти предел.

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(1)

lim⁡x→0tg⁡2x−tg⁡x2earcsin⁡x−esin⁡x−x3/2\lim_{x \rightarrow 0} \frac{\operatorname {tg}^{2} x-\operatorname {tg} x^{2}}{e^{\arcsin x}-e^{\sin x}-x^{3} / 2},

(2)

lim⁡x→0ln⁡(sin⁡x/x)+ch⁡(x/3)−1sh⁡x−ln⁡(x+1+x2)\lim_{x \rightarrow 0} \frac{\ln (\sin x / x)+\operatorname {ch}(x / \sqrt{3})-1}{\operatorname {sh} x-\ln \left(x+\sqrt{1+x^{2}}\right)},

(3)

lim⁡x→03arctg⁡sin⁡x−tg⁡sh⁡3x1+xsin⁡x3−x2ln⁡(1−16x/9)\lim_{x \rightarrow 0} \frac{3 \operatorname {arctg} \sin x-\operatorname {tg} \operatorname {sh} 3 x}{\sqrt{1+x} \sin x^{3}-x^{2} \ln (1-16 x / 9)},

(4)

lim⁡x→0sin⁡1+x3−sin⁡11−2xln⁡cos⁡x5−1\lim_{x \rightarrow 0} \frac{\sin \sqrt{1+x^{3}}-\sin 1}{\sqrt[5]{1-2 x \ln \cos x}-1}

(5)

lim⁡x→0arctg⁡(3+x2)−arctg⁡(2+cos⁡x)ln⁡(1+x)−ex+1\lim_{x \rightarrow 0} \frac{\operatorname {arctg}\left(3+x^{2}\right)-\operatorname {arctg}(2+\cos x)}{\ln (1+x)-e^{x}+1},

(6)

lim⁡x→0arcsin⁡(1/2+x2)−arcsin⁡(cos⁡x−1/2)1+ln⁡(1+x2)−cos⁡x\lim_{x \rightarrow 0} \frac{\arcsin \left(1 / 2+x^{2}\right)-\arcsin (\cos x-1 / 2)}{1+\ln \left(1+x^{2}\right)-\cos x}

Задача 1.19.16

Найти предел.

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(1)

lim⁡x→0ex2−1+2x2tg⁡4x\lim_{x \rightarrow 0} \frac{e^{x^{2}}-\sqrt{1+2 x^{2}}}{\operatorname {tg}^{4} x},

(2)

lim⁡x→0ex+ln⁡(1−sin⁡x)−18−x43−2\lim_{x \rightarrow 0} \frac{e^{x}+\ln (1-\sin x)-1}{\sqrt[3]{8-x^{4}}-2},

(3)

lim⁡x→0ln⁡(cos⁡x+x2/2)e−x2/2−cos⁡x\lim_{x \rightarrow 0} \frac{\ln \left(\cos x+x^{2} / 2\right)}{e^{-x^{2} / 2}-\cos x},

(4)

lim⁡x→0ex/(1+x)−cos⁡(1−e−x)−arctg⁡xx4\lim_{x \rightarrow 0} \frac{e^{x /(1+x)}-\cos \left(1-e^{-x}\right)-\operatorname {arctg} x}{x^{4}},

(5)

lim⁡x→0xex−1+2x−x6−x73(1/e)(1+x)1/x−1−x+7x2/6\lim_{x \rightarrow 0} \frac{x \sqrt{e^{x}-\sqrt{1+2 x}-\sqrt[3]{x^{6}-x^{7}}}}{(1 / e)(1+x)^{1 / x}-\sqrt{1-x+7 x^{2} / 6}}

(6)

lim⁡x→0xln⁡(1+x)+cos⁡x+4x3/3−1+3x31−x+x2/2−(cos⁡x)1/x\lim_{x \rightarrow 0} \frac{x \sqrt{\ln (1+x)+\cos x+4 x^{3} / 3-\sqrt[3]{1+3 x}}}{\sqrt{1-x+x^{2} / 2}-(\cos x)^{1 / x}}

Задача 1.19.17

Найти предел.

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(1)

lim⁡x→0sin⁡(xex)+sin⁡(xe−x)−2x−2x3/3x5\lim_{x \rightarrow 0} \frac{\sin \left(x e^{x}\right)+\sin \left(x e^{-x}\right)-2 x-2 x^{3} / 3}{x^{5}},

(2)

lim⁡x→0sin⁡(xcos⁡x)+xln⁡(1+2x2/3)−x1+x2−1\lim_{x \rightarrow 0} \frac{\sin (x \cos x)+x \ln \left(1+2 x^{2} / 3\right)-x}{\sqrt{1+x^{2}}-1}

(3)

lim⁡x→01−x2/23−e−x2/6x2ln⁡(1+x)−(tg⁡x3)cos⁡sh⁡(x/2)\lim_{x \rightarrow 0} \frac{\sqrt[3]{1-x^{2} / 2}-e^{-x^{2} / 6}}{x^{2} \ln (1+x)-\left(\operatorname {tg} x^{3}\right) \cos \operatorname {sh}(x / 2)}

(4)

lim⁡x→0ln⁡(cos⁡x+xsin⁡x)−(x2/2)ex(x/2)1−x3+1+x2/3−sin⁡(x/2)−1\lim_{x \rightarrow 0} \frac{\ln (\cos x+x \sin x)-\left(x^{2} / 2\right) e^{x}}{(x / 2) \sqrt[3]{1-x}+\sqrt{1+x^{2} / 3}-\sin (x / 2)-1}

Задача 1.19.18

Найти предел.

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(1)

lim⁡x→0ecos⁡x−e1−4x23(1/x)arcsin⁡2x−2ch⁡x2\lim_{x \rightarrow 0} \frac{e^{\cos x}-e \sqrt[3]{1-4 x^{2}}}{(1 / x) \arcsin 2 x-2 \operatorname {ch} x^{2}},

(2)

lim⁡x→0ln⁡(1+2x−tg⁡x)+(1/2)arctg⁡x2xex2−sin⁡x\lim_{x \rightarrow 0} \frac{\ln (\sqrt{1+2 x}-\operatorname {tg} x)+(1 / 2) \operatorname {arctg} x^{2}}{x e^{x^{2}}-\sin x},

(3)

lim⁡x→01−2x−e−x+x21+x3sin⁡2x−ln⁡ch⁡2x\lim_{x \rightarrow 0} \frac{\sqrt{1-2 x}-e^{-x}+x^{2} \sqrt[3]{1+x}}{\sin^{2} x-\ln \operatorname {ch}^{2} x},

(4)

lim⁡x→0ln⁡(1+x)+(1/2)sh⁡x2−x1+tg⁡x−1+sin⁡x\lim_{x \rightarrow 0} \frac{\ln (1+x)+(1 / 2) \operatorname {sh} x^{2}-x}{\sqrt{1+\operatorname {tg} x}-\sqrt{1+\sin x}}

(5)

lim⁡x→0((1+3x)1/3−1)/tg⁡x−e−sh⁡x−x2(x+5)/(x+6)ln⁡(2ex2−1)/sin⁡x−arctg⁡2x\lim_{x \rightarrow 0} \frac{\left((1+3 x)^{1 / 3}-1\right) / \operatorname {tg} x-e^{-\operatorname {sh} x}-x^{2}(x+5) /(x+6)}{\ln \left(2 e^{x^{2}}-1\right) / \sin x-\operatorname {arctg} 2 x},

(6)

lim⁡x→0(cos⁡2x+sh⁡2x−ex)/x+2x(2−x)/(2+x)(ln⁡ch⁡x)/sh⁡x−(1/2)arcsin⁡x\lim_{x \rightarrow 0} \frac{\left(\sqrt{\cos 2 x+\operatorname {sh} 2 x}-e^{x}\right) / x+2 x(2-x) /(2+x)}{(\ln \operatorname {ch} x) / \operatorname {sh} x-(1 / 2) \arcsin x}.

Задача 1.19.19

Найти числа α∈R\alpha \in \mathbb {R} и n∈Nn \in \mathbb {N} такие, чтобы существовал конечный предел lim⁡x→0eαxn−cos⁡x2x8\lim_{x \rightarrow 0} \frac{e^{\alpha x^{n}}-\cos x^{2}}{x^{8}}.

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Задача 1.19.20

Найти предел.

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(1)

lim⁡x→0(1+x−x)1/x\lim_{x \rightarrow 0}(\sqrt{1+x}-x)^{1 / x};

(2)

lim⁡x→0(cos⁡x)ctg⁡2x\lim_{x \rightarrow 0}(\cos x)^{\operatorname {ctg}^{2} x}

(3)

lim⁡x→0(ch⁡x)1/sin⁡2x\lim_{x \rightarrow 0}(\operatorname {ch} x)^{1 / \sin^{2} x};

(4)

lim⁡x→0(cos⁡xch⁡3x)1/x2\lim_{x \rightarrow 0}\left(\frac{\cos x}{\operatorname {ch} 3 x}\right)^{1 / x^{2}}

(5)

lim⁡x→0(ex2ch⁡3x)1/x2\lim_{x \rightarrow 0}\left(\frac{e^{x^{2}}}{\operatorname {ch} 3 x}\right)^{1 / x^{2}}

(6)

lim⁡x→0(ln⁡(e+x)−xe)1/sin⁡3x\lim_{x \rightarrow 0}\left(\ln (e+x)-\frac{x}{e}\right)^{1 / \sin^{3} x}.

Задача 1.19.21

Найти предел.

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(1)

lim⁡x→0(arcsin⁡xx)1/x2\lim_{x \rightarrow 0}\left(\frac{\arcsin x}{x}\right)^{1 / x^{2}};

(2)

lim⁡x→0(ln⁡(1+x2+x)x)1/x2\lim_{x \rightarrow 0}\left(\frac{\ln \left(\sqrt{1+x^{2}}+x\right)}{x}\right)^{1 / x^{2}}

(3)

lim⁡x→0(sin⁡xarcsin⁡x)1/x2\lim_{x \rightarrow 0}\left(\frac{\sin x}{\arcsin x}\right)^{1 / x^{2}};

(4)

lim⁡x→0(tg⁡xarctg⁡x)1/x2\lim_{x \rightarrow 0}\left(\frac{\operatorname {tg} x}{\operatorname {arctg} x}\right)^{1 / x^{2}}.

Задача 1.19.22

Найти предел.

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(1)

lim⁡x→0(sin⁡x2(1+x−1))ctg⁡x\lim_{x \rightarrow 0}\left(\frac{\sin x}{2(\sqrt{1+x}-1)}\right)^{\operatorname {ctg} x};

(2)

lim⁡x→0(1−2x−1−3x3ln⁡ch⁡x)1/x\lim_{x \rightarrow 0}\left(\frac{\sqrt{1-2 x}-\sqrt[3]{1-3 x}}{\ln \operatorname {ch} x}\right)^{1 / x};

(3)

lim⁡x→0(1xex/(1+x)−1sin⁡x)1/arctg⁡x\lim_{x \rightarrow 0}\left(\frac{1}{x} e^{x /(1+x)}-\frac{1}{\sin x}\right)^{1 / \operatorname {arctg} x};

(4)

lim⁡x→0(tg⁡3x+cos⁡4x−cos⁡2xln⁡1+3x−ln⁡1−3x)1/sin⁡x\lim_{x \rightarrow 0}\left(\frac{\operatorname {tg} 3 x+\cos 4 x-\cos 2 x}{\ln \sqrt{1+3 x}-\ln \sqrt{1-3 x}}\right)^{1 / \sin x}.

Задача 1.19.23

Найти предел.

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(1)

lim⁡x→0(1+6x−sin⁡xx2)2(ch⁡x−1)/x2\lim_{x \rightarrow 0}\left(1+6 \frac{x-\sin x}{x^{2}}\right)^{2(\operatorname {ch} x-1) / x^{2}};

(2)

lim⁡x→0(e2−(1+2x)1/x2xe2)1/x\lim_{x \rightarrow 0}\left(\frac{e^{2}-(1+2 x)^{1 / x}}{2 x e^{2}}\right)^{1 / x};

(3)

lim⁡x→0(ch⁡x−cos⁡x21+2x−21+3x3)1/x\lim_{x \rightarrow 0}\left(\frac{\operatorname {ch} x-\cos x}{2 \sqrt{1+2 x}-2 \sqrt[3]{1+3 x}}\right)^{1 / x}.

Задача 1.19.24

Найти предел.

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(1)

lim⁡x→0(1+tg⁡2x+ln⁡(1−x))1/x2\lim_{x \rightarrow 0}(\sqrt{1+\operatorname {tg} 2 x}+\ln (1-x))^{1 / x^{2}};

(2)

lim⁡x→0(tg⁡(x/3)+2−1+x3)ctg⁡2x\lim_{x \rightarrow 0}(\operatorname {tg}(x / 3)+2-\sqrt[3]{1+x})^{\operatorname {ctg}^{2} x};

(3)

lim⁡x→0(e(1/3)sin⁡x+1−tg⁡x3−1)1/ln⁡(1+x2)\lim_{x \rightarrow 0}\left(e^{(1 / 3) \sin x}+\sqrt[3]{1-\operatorname {tg} x}-1\right)^{1 / \ln \left(1+x^{2}\right)};

(4)

lim⁡x→0(1e(1+x)1/x+2x4+5x)ctg⁡2x\lim_{x \rightarrow 0}\left(\frac{1}{e}(1+x)^{1 / x}+\frac{2 x}{4+5 x}\right)^{\operatorname {ctg}^{2} x}.

Задача 1.19.25

Найти предел.

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(1)

lim⁡x→0(arctg⁡xex−1−x2/2)1/x2\lim_{x \rightarrow 0}\left(\frac{\operatorname {arctg} x}{e^{x}-1-x^{2} / 2}\right)^{1 / x^{2}};

(2)

lim⁡x→0(xsh⁡xln⁡(1+x2))ctg⁡2x\lim_{x \rightarrow 0}\left(\frac{x \operatorname {sh} x}{\ln \left(1+x^{2}\right)}\right)^{\operatorname {ctg}^{2} x};

(3)

lim⁡x→0(2cos⁡x+x21+x)1/x2\lim_{x \rightarrow 0}\left(\frac{2 \cos x+x}{2 \sqrt{1+x}}\right)^{1 / x^{2}};

(4)

lim⁡x→0(xsin⁡x2ch⁡x−2)1/x2\lim_{x \rightarrow 0}\left(\frac{x \sin x}{2 \operatorname {ch} x-2}\right)^{1 / x^{2}}.

Задача 1.19.26

Найти предел.

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(1)

lim⁡x→0(1+x−1−xsh⁡x)1/sin⁡2x\lim_{x \rightarrow 0}\left(\frac{\sqrt{1+x}-\sqrt{1-x}}{\operatorname {sh} x}\right)^{1 / \sin^{2} x};

(2)

lim⁡x→0(1+x2−1+x2ch⁡x−1)1/x2\lim_{x \rightarrow 0}\left(\frac{1+x^{2}-\sqrt{1+x^{2}}}{\operatorname {ch} x-1}\right)^{1 / x^{2}};

(3)

lim⁡x→0(cos⁡xex−ln⁡(1+x))1/x2\lim_{x \rightarrow 0}\left(\frac{\sqrt{\cos x}}{e^{x}-\ln (1+x)}\right)^{1 / x^{2}}

(4)

lim⁡x→0(cos⁡x1+tg⁡x2)1/x2\lim_{x \rightarrow 0}\left(\frac{\sqrt{\cos x}}{\sqrt{1+\operatorname {tg} x^{2}}}\right)^{1 / x^{2}}.

Задача 1.19.27

Найти предел.

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(1)

lim⁡x→0((arcsin⁡x)2−x2sin⁡2(x2/3))1/sin⁡2x\lim_{x \rightarrow 0}\left(\frac{(\arcsin x)^{2}-x^{2}}{\sin^{2}\left(x^{2} / \sqrt{3}\right)}\right)^{1 / \sin^{2} x};

(2)

lim⁡x→0(arctg⁡(2x/(2−x2))−xxsin⁡(x2/6))ctg⁡2x\lim_{x \rightarrow 0}\left(\frac{\operatorname {arctg}\left(2 x /\left(2-x^{2}\right)\right)-x}{x \sin \left(x^{2} / 6\right)}\right)^{\operatorname {ctg}^{2} x};

(3)

lim⁡x→0(x2−(arctg⁡x)2x2sin⁡(2x2/3))1/x2\lim_{x \rightarrow 0}\left(\frac{x^{2}-(\operatorname {arctg} x)^{2}}{x^{2} \sin \left(2 x^{2} / 3\right)}\right)^{1 / x^{2}};

(4)

lim⁡x→0(3arccos⁡(1−2x2)−6xx3)1/x2\lim_{x \rightarrow 0}\left(\frac{3 \arccos \left(1-2 x^{2}\right)-6 x}{x^{3}}\right)^{1 / x^{2}}.

Задача 1.19.28

Найти предел.

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(1)

lim⁡x→0(2ex−x2−22x−x2)(sin⁡x)/x3\lim_{x \rightarrow 0}\left(\frac{2 e^{x-x^{2}}-2}{2 x-x^{2}}\right)^{(\sin x) / x^{3}};

(2)

lim⁡x→0(cos⁡x1+x−(1/2)sh⁡x)1/arcsin⁡x2\lim_{x \rightarrow 0}\left(\frac{\sqrt{\cos x}}{\sqrt{1+x}-(1 / 2) \operatorname {sh} x}\right)^{1 / \arcsin x^{2}};

(3)

lim⁡x→0(sh⁡(x+sin⁡x)sin⁡x+arcsin⁡x)ctg⁡2x\lim_{x \rightarrow 0}\left(\frac{\operatorname {sh}(x+\sin x)}{\sin x+\arcsin x}\right)^{\operatorname {ctg}^{2} x}.

Задача 1.19.29

Найти предел.

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(1)

lim⁡x→0(ln⁡(1+x)x+xln⁡(e2−xe2))1/x2\lim_{x \rightarrow 0}\left(\frac{\ln (1+x)}{x}+\frac{x}{\ln \left(e^{2}-x e^{2}\right)}\right)^{1 / x^{2}};

(2)

lim⁡x→0(arcsin⁡5x−arcsin⁡3x−arctg⁡xx)1/ln⁡cos⁡3x\lim_{x \rightarrow 0}\left(\frac{\arcsin 5 x-\arcsin 3 x-\operatorname {arctg} x}{x}\right)^{1 / \ln \cos 3 x};

(3)

lim⁡x→0(sin⁡(2x+x3)−sh⁡(x+2x3)x)1/(2ln⁡(1+x2)−ln⁡2(1+x))\lim_{x \rightarrow 0}\left(\frac{\sin \left(2 x+x^{3}\right)-\operatorname {sh}\left(x+2 x^{3}\right)}{x}\right)^{1 /\left(2 \ln \left(1+x^{2}\right)-\ln^{2}(1+x)\right)};

(4)

lim⁡x→0(tg⁡(2x+x3)−th⁡(x+2x3)x)1/(1+x33−1+x2)\lim_{x \rightarrow 0}\left(\frac{\operatorname {tg}\left(2 x+x^{3}\right)-\operatorname {th}\left(x+2 x^{3}\right)}{x}\right)^{1 /\left(\sqrt[3]{1+x^{3}}-\sqrt{1+x^{2}}\right)}.

Задача 1.19.30

Найти предел.

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(1)

lim⁡x→0(cos⁡2x+xex1−x−x)1/x3\lim_{x \rightarrow 0}\left(\cos 2 x+\frac{x e^{x}}{1-x}-x\right)^{1 / x^{3}};

(2)

lim⁡x→0(1+2x+x33−2x2x+3)1/x3\lim_{x \rightarrow 0}\left(\sqrt[3]{1+2 x+x^{3}}-\frac{2 x}{2 x+3}\right)^{1 / x^{3}};

(3)

lim⁡x→0(2xx−2+ln⁡(e+xex+1))1/x3\lim_{x \rightarrow 0}\left(\frac{2 x}{x-2}+\ln \left(e+x e^{x+1}\right)\right)^{1 / x^{3}};

(4)

lim⁡x→0(2−x2+x+sin⁡ln⁡(1+x))1/x3\lim_{x \rightarrow 0}\left(\frac{2-x}{2+x}+\sin \ln (1+x)\right)^{1 / x^{3}}.

Задача 1.19.31

Найти предел.

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(1)

lim⁡x→0(x−ln⁡(1+x)+cos⁡(xe−x))1/x3\lim_{x \rightarrow 0}\left(x-\ln (1+x)+\cos \left(x e^{-x}\right)\right)^{1 / x^{3}};

(2)

lim⁡x→0(esin⁡x−e2x−x2+etg⁡x)1/x3\lim_{x \rightarrow 0}\left(e^{\sin x}-e^{2 x-x^{2}}+e^{\operatorname {tg} x}\right)^{1 / x^{3}};

(3)

lim⁡x→0(1+12ln⁡1+x1−x−arctg⁡x)1/arcsin⁡x3\lim_{x \rightarrow 0}\left(1+\frac{1}{2} \ln \frac{1+x}{1-x}-\operatorname {arctg} x\right)^{1 / \arcsin x^{3}};

(4)

lim⁡x→0(ex−x1+x2−ln⁡(1+x3))1/x3\lim_{x \rightarrow 0}\left(\frac{e^{x}-x}{\sqrt{1+x^{2}}-\ln \left(1+x^{3}\right)}\right)^{1 / x^{3}}.

Задача 1.19.32

Найти предел.

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(1)

lim⁡x→0(8+x33−cos⁡x2)1/arcsin⁡x3\lim_{x \rightarrow 0}\left(\sqrt[3]{8+x^{3}}-\cos x^{2}\right)^{1 / \arcsin x^{3}};

(2)

lim⁡x→0(cos⁡x−x+earctg⁡x−1)1/sin⁡3x\lim_{x \rightarrow 0}\left(\cos x-x+e^{\operatorname {arctg} x}-1\right)^{1 / \sin^{3} x};

(3)

lim⁡x→0(32x2+1+3sin⁡x3+ln⁡(1−x))1/sh⁡3x\lim_{x \rightarrow 0}\left(\frac{3}{2} x^{2}+\sqrt[3]{1+3 \sin x}+\ln (1-x)\right)^{1 / \operatorname {sh}^{3} x};

(4)

lim⁡x→0(1−3xcos⁡2x3+4x2+x1+3x)1/(arcsin⁡x)3\lim_{x \rightarrow 0}\left(\sqrt[3]{1-3 x \cos 2 x}+4 x^{2}+\frac{x}{1+3 x}\right)^{1 /(\arcsin x)^{3}}.

Задача 1.19.33

Найти предел.

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(1)

lim⁡x→0(etg⁡x+ln⁡(1−x))ctg⁡x3\lim_{x \rightarrow 0}\left(e^{\operatorname {tg} x}+\ln (1-x)\right)^{\operatorname {ctg} x^{3}};

(2)

lim⁡x→0(1+sin⁡x−(1/2)tg⁡x+x2/8)ctg⁡x3\lim_{x \rightarrow 0}\left(\sqrt{1+\sin x}-(1 / 2) \operatorname {tg} x+x^{2} / 8\right)^{\operatorname {ctg} x^{3}};

(3)

lim⁡x→0(1−2x+3x2+x(1−sh⁡x))ctg⁡3x\lim_{x \rightarrow 0}\left(\sqrt{1-2 x+3 x^{2}}+x(1-\operatorname {sh} x)\right)^{\operatorname {ctg}^{3} x};

(4)

lim⁡x→0(esin⁡x−x2/2+cos⁡x−1+2x)1/tg⁡x3\lim_{x \rightarrow 0}\left(e^{\sin x}-x^{2} / 2+\cos x-\sqrt{1+2 x}\right)^{1 / \operatorname {tg} x^{3}}.

Задача 1.19.34

Найти предел.

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(1)

lim⁡x→0(ln⁡(1−x)+excos⁡x)1/(x2(1+3x−1))\lim_{x \rightarrow 0}\left(\ln (1-x)+e^{x \cos x}\right)^{1 /\left(x^{2}(\sqrt{1+3 x}-1)\right)};

(2)

lim⁡x→0((2/π)arccos⁡x+sin⁡(2x/π))1/(1+2x3−1)\lim_{x \rightarrow 0}((2 / \pi ) \arccos x+\sin (2 x / \pi ))^{1 /\left(\sqrt{1+2 x^{3}}-1\right)};

(3)

lim⁡x→0(1+th⁡(xex)+(1/2)ln⁡(1−2x))1/x3\lim_{x \rightarrow 0}\left(1+\operatorname {th}\left(x e^{x}\right)+(1 / 2) \ln (1-2 x)\right)^{1 / x^{3}}.

Задача 1.19.35

Найти предел.

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(1)

lim⁡x→0(earctg⁡x−1/(1−x)+cos⁡x+x2)1/sin⁡x3\lim_{x \rightarrow 0}\left(e^{\operatorname {arctg} x}-1 /(1-x)+\cos x+x^{2}\right)^{1 / \sin x^{3}};

(2)

lim⁡x→0(1+2arctg⁡x−sh⁡2x)1/ln⁡3(1−x)\lim_{x \rightarrow 0}(1+2 \operatorname {arctg} x-\operatorname {sh} 2 x)^{1 / \ln^{3}(1-x)};

(3)

lim⁡x→0(esin⁡x−x2/2−xcos⁡x)1/ln⁡3(1−x/2)\lim_{x \rightarrow 0}\left(e^{\sin x}-x^{2} / 2-x \cos x\right)^{1 / \ln^{3}(1-x / 2)}.

Задача 1.19.36

Найти предел.

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(1)

lim⁡x→0(1+tg⁡x3−(x/3)e−x/3)1/(xln⁡cos⁡x)\lim_{x \rightarrow 0}\left(\sqrt[3]{1+\operatorname {tg} x}-(x / 3) e^{-x / 3}\right)^{1 /(x \ln \cos x)};

(2)

lim⁡x→0(e−x1−x+12(ln⁡1+2x−tg⁡x))1/(x(cos⁡x−1))\lim_{x \rightarrow 0}\left(\frac{e^{-x}}{1-x}+\frac{1}{2}(\ln \sqrt{1+2 x}-\operatorname {tg} x)\right)^{1 /(x(\cos x-1))};

(3)

lim⁡x→0(ex−x2−x1−3x/23)1/(tg⁡x−x)\lim_{x \rightarrow 0}\left(e^{x-x^{2}}-x \sqrt[3]{1-3 x / 2}\right)^{1 /(\operatorname {tg} x-x)}.

Задача 1.19.37

Найти предел.

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(1)

lim⁡x→0(1+2tg⁡x+x2/2−sin⁡x)1/(sh⁡x−arctg⁡x)\lim_{x \rightarrow 0}\left(\sqrt{1+2 \operatorname {tg} x}+x^{2} / 2-\sin x\right)^{1 /(\operatorname {sh} x-\operatorname {arctg} x)};

(2)

lim⁡x→0(1−sin⁡x+arctg⁡x)1/(sh⁡x−sin⁡x)\lim_{x \rightarrow 0}(1-\sin x+\operatorname {arctg} x)^{1 /(\operatorname {sh} x-\sin x)};

(3)

lim⁡x→0(1+1−xln⁡(1+x)−x/(1+x))1/(tg⁡x−sh⁡x)\lim_{x \rightarrow 0}(1+\sqrt{1-x} \ln (1+x)-x /(1+x))^{1 /(\operatorname {tg} x-\operatorname {sh} x)};

(4)

lim⁡x→0(cos⁡(sin⁡x)+(1/2)arctg⁡x2+4x3)1/(tg⁡x−sh⁡x)\lim_{x \rightarrow 0}\left(\cos (\sin x)+(1 / 2) \operatorname {arctg} x^{2}+4 x^{3}\right)^{1 /(\operatorname {tg} x-\operatorname {sh} x)}.

Задача 1.19.38

Найти предел.

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(1)

lim⁡x→0(esin⁡2x−2x−2x2)1/sin⁡x4\lim_{x \rightarrow 0}\left(e^{\sin 2 x}-2 x-2 x^{2}\right)^{1 / \sin x^{4}};

(2)

lim⁡x→0(esin⁡x+ln⁡(1−x)+x3/3)1/x4\lim_{x \rightarrow 0}\left(e^{\sin x}+\ln (1-x)+x^{3} / 3\right)^{1 / x^{4}};

(3)

lim⁡x→0(x+sin⁡x−ln⁡(x+1+x2)x)1/x4\lim_{x \rightarrow 0}\left(\frac{x+\sin x-\ln \left(x+\sqrt{1+x^{2}}\right)}{x}\right)^{1 / x^{4}};

(4)

lim⁡x→0(arctg⁡(sh⁡x)sin⁡x)1/sin⁡4x\lim_{x \rightarrow 0}\left(\frac{\operatorname {arctg}(\operatorname {sh} x)}{\sin x}\right)^{1 / \sin^{4} x};

(5)

lim⁡x→0(arcsin⁡(xcos⁡x)arctg⁡x)1/sin⁡x4\lim_{x \rightarrow 0}\left(\frac{\arcsin (x \cos x)}{\operatorname {arctg} x}\right)^{1 / \sin x^{4}}

Задача 1.19.39

Найти предел.

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(1)

lim⁡x→0(1+sin⁡xarcsin⁡x−x2ex2)1/sin⁡2x2\lim_{x \rightarrow 0}\left(1+\sin x \arcsin x-x^{2} e^{x^{2}}\right)^{1 / \sin^{2} x^{2}};

(2)

lim⁡x→0(1+tg⁡xarctg⁡x−x2ch⁡2x)1/(1−cos⁡x)2\lim_{x \rightarrow 0}\left(1+\operatorname {tg} x \operatorname {arctg} x-x^{2} \operatorname {ch}^{2} x\right)^{1 /(1-\cos x)^{2}};

(3)

lim⁡x→0(1+th⁡xln⁡1+x1−x−2x2cos⁡x2)1/x4\lim_{x \rightarrow 0}\left(1+\operatorname {th} x \ln \frac{1+x}{1-x}-2 x^{2} \cos x^{2}\right)^{1 / x^{4}};

(4)

lim⁡x→0(log⁡2(3−4x1−2x−1+4x1+2x))2sh⁡x/(x−sin⁡x)\lim_{x \rightarrow 0}\left(\log_{2}\left(\frac{3-4 x}{1-2 x}-\frac{1+4 x}{1+2 x}\right)\right)^{2 \operatorname {sh} x /(x-\sin x)}.

Задача 1.19.40

Найти предел.

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(1)

lim⁡x→0(1+sh⁡xln⁡(x+1+x2)−x2cos⁡x2)1/x4\lim_{x \rightarrow 0}\left(1+\operatorname {sh} x \ln \left(x+\sqrt{1+x^{2}}\right)-x^{2} \cos x^{2}\right)^{1 / x^{4}};

(2)

lim⁡x→0(cos⁡sin⁡x+(1/2)arctg⁡x2)1/sin⁡x4\lim_{x \rightarrow 0}\left(\cos \sin x+(1 / 2) \operatorname {arctg} x^{2}\right)^{1 / \sin x^{4}};

(3)

lim⁡x→0(ch⁡x+2cos⁡x3+x26(1+x2))1/arctg⁡x4\lim_{x \rightarrow 0}\left(\frac{\operatorname {ch} x+2 \cos x}{3}+\frac{x^{2}}{6\left(1+x^{2}\right)}\right)^{1 / \operatorname {arctg} x^{4}}.

Задача 1.19.41

Найти предел.

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(1)

lim⁡x→0(2xsin⁡2x−23x2)x2/(x2−arctg⁡x2)\lim_{x \rightarrow 0}\left(\frac{2 x}{\sin 2 x}-\frac{2}{3} x^{2}\right)^{x^{2} /\left(x^{2}-\operatorname {arctg} x^{2}\right)},

(2)

lim⁡x→0(cos⁡x+x2x+1/4)(x+e)/arcsin⁡x3\lim_{x \rightarrow 0}\left(\cos x+x^{2} \sqrt{x+1 / 4}\right)^{(x+e) / \arcsin x^{3}};

(3)

lim⁡x→0(1+3x3−tg⁡sin⁡x+x2)1/(arctg⁡x−xcos⁡x)\lim_{x \rightarrow 0}\left(\sqrt[3]{1+3 x}-\operatorname {tg} \sin x+x^{2}\right)^{1 /(\operatorname {arctg} x-x \cos x)};

(4)

lim⁡x→0(1−(1+x2)1/x2−ecos⁡xe)1/(ch⁡2x−ex2)\lim_{x \rightarrow 0}\left(1-\frac{\left(1+x^{2}\right)^{1 / x^{2}}-e^{\cos x}}{e}\right)^{1 /\left(\sqrt{\operatorname {ch} 2 x}-e^{x^{2}}\right)}.

Задача 1.19.42

Найти предел.

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(1)

lim⁡x→0(cos⁡(2x+x2)+2arcsin⁡(xex)−2x)ctg⁡3x+1/(3x3)\lim_{x \rightarrow 0}\left(\cos \left(2 x+x^{2}\right)+2 \arcsin \left(x e^{x}\right)-2 x\right)^{\operatorname {ctg}^{3} x+1 /\left(3 x^{3}\right)};

(2)

lim⁡x→0(1+arcsin⁡x3)ex/(xcos⁡x3−sin⁡x+tg⁡3x)\lim_{x \rightarrow 0}\left(1+\arcsin x^{3}\right)^{e^{x} /\left(x \sqrt[3]{\cos x}-\sin x+\operatorname {tg}^{3} x\right)}.

Задача 1.19.43

Доказать, что:

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(1)

lim⁡x→0(2π)1/x3(arccos⁡sh⁡x+x)ctg⁡x3=e−2/(3π)\lim_{x \rightarrow 0}\left(\frac{2}{\pi }\right)^{1 / x^{3}}(\arccos \operatorname {sh} x+x)^{\operatorname {ctg} x^{3}} = e^{-2 /(3 \pi )};

(2)

lim⁡x→0(6πarcsin⁡(12eπx2)+sh⁡2x)1/x2=e1+23\lim_{x \rightarrow 0}\left(\frac{6}{\pi } \arcsin \left(\frac{1}{2} e^{\pi x^{2}}\right)+\operatorname {sh}^{2} x\right)^{1 / x^{2}} = e^{1+2 \sqrt{3}};

(3)

lim⁡x→0(4arctg⁡(ch⁡3x)+sin⁡2xπ)1/x2=e10/π\lim_{x \rightarrow 0}\left(\frac{4 \operatorname {arctg}(\operatorname {ch} 3 x)+\sin^{2} x}{\pi }\right)^{1 / x^{2}} = e^{10 / \pi }.

Задача 1.19.44

Найти предел.

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(1)

lim⁡x→0(2ln⁡(1+x)x2−2(x+1)sh⁡x)ctg⁡x\lim_{x \rightarrow 0}\left(\frac{2 \ln (1+x)}{x^{2}}-\frac{2}{(x+1) \operatorname {sh} x}\right)^{\operatorname {ctg} x};

(2)

lim⁡x→0(6ln⁡(1+3sin⁡2x)−4ln⁡(2−cos⁡2x))1/x2\lim_{x \rightarrow 0}\left(\frac{6}{\ln \left(1+3 \sin^{2} x\right)}-\frac{4}{\ln (2-\cos 2 x)}\right)^{1 / x^{2}}.

Задача 1.19.45

Найти предел.

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(1)

lim⁡x→+∞(ch⁡x)x2(tg⁡(1/x)−arctg⁡(1/x))\lim_{x \rightarrow +\infty }(\operatorname {ch} x)^{x^{2}(\operatorname {tg}(1 / x)-\operatorname {arctg}(1 / x))};

(2)

lim⁡x→∞e−x2/3(x2ln⁡x+1x−1)x4\lim_{x \rightarrow \infty } e^{-x^{2} / 3}\left(\frac{x}{2} \ln \frac{x+1}{x-1}\right)^{x^{4}};

(3)

lim⁡x→∞(x4+x2+1x4−x2−1)x4sin⁡2(1/x)\lim_{x \rightarrow \infty }\left(\frac{x^{4}+x^{2}+1}{x^{4}-x^{2}-1}\right)^{x^{4} \sin^{2}(1 / x)}.

Задача 1.19.46

Найти предел.

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(1)

lim⁡x→+∞(x2−xx+14sin⁡2x)x2+sin⁡3x\lim_{x \rightarrow +\infty }\left(\frac{\sqrt{x^{2}-x}}{x}+\frac{1}{4} \sin \frac{2}{x}\right)^{x^{2}+\sin 3 x};

(2)

lim⁡x→+∞(xln⁡(1+x)−xln⁡x+arctg⁡12x)x2arctg⁡x\lim_{x \rightarrow +\infty }\left(x \ln (1+x)-x \ln x+\operatorname {arctg} \frac{1}{2 x}\right)^{x^{2} \operatorname {arctg} x};

(3)

lim⁡x→+∞(ln⁡(tg⁡2ln⁡x+1x−sh⁡21x+1x3)+4ln⁡x)\lim_{x \rightarrow +\infty }\left(\ln \left(\operatorname {tg}^{2} \ln \frac{x+1}{x}-\operatorname {sh}^{2} \frac{1}{x}+\frac{1}{x^{3}}\right)+4 \ln x\right);

(4)

lim⁡x→+∞e−x2/2(x2+2x−x2−2x2)x4\lim_{x \rightarrow +\infty } e^{-x^{2} / 2}\left(\frac{\sqrt{x^{2}+2 x}-\sqrt{x^{2}-2 x}}{2}\right)^{x^{4}}.

Задача 1.19.47

Найти предел.

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(1)

lim⁡x→+0(sh⁡x−ln⁡(x+1+x2))1/ln⁡x\lim_{x \rightarrow +0}\left(\operatorname {sh} x-\ln \left(x+\sqrt{1+x^{2}}\right)\right)^{1 / \ln x};

(2)

lim⁡x→+0(x/3+ctg⁡x−(1/x)cos⁡(x2/3))1/ln⁡sin⁡x\lim_{x \rightarrow +0}\left(x / 3+\operatorname {ctg} x-(1 / x) \cos \left(x^{2} / 3\right)\right)^{1 / \ln \sin x};

(3)

lim⁡x→+0(xsin⁡x−sh⁡xx+sin⁡4x10)1/ln⁡tg⁡x\lim_{x \rightarrow +0}\left(\frac{x}{\sin x}-\frac{\operatorname {sh} x}{x}+\frac{\sin^{4} x}{10}\right)^{1 / \ln \operatorname {tg} x};

(4)

lim⁡x→+0(1+1sin⁡x−1arcsin⁡x)1/x+ln⁡2x\lim_{x \rightarrow +0}\left(1+\frac{1}{\sin x}-\frac{1}{\arcsin x}\right)^{1 / x+\ln^{2} x};

(5)

lim⁡x→+0(sh⁡xarctg⁡x)1/x2+ln⁡x\lim_{x \rightarrow +0}\left(\frac{\operatorname {sh} x}{\operatorname {arctg} x}\right)^{1 / x^{2}+\ln x}.

Задача 1.19.48

Найти предел. lim⁡x→π/2−0((π/2−x)tg⁡x)tg⁡x\lim_{x \rightarrow \pi / 2-0}((\pi / 2-x) \operatorname {tg} x)^{\operatorname {tg} x}.

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Задача 1.19.49

Найти предел.

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(1)

lim⁡x→1(ex−1−ln⁡x)1/(sin⁡(x−1)+cos⁡(x−1)−x)\lim_{x \rightarrow 1}\left(e^{x-1}-\ln x\right)^{1 /(\sin (x-1)+\cos (x-1)-x)};

(2)

lim⁡x→1(esin⁡(x−1)−ln⁡x)ctg⁡2(x−1)\lim_{x \rightarrow 1}\left(e^{\sin (x-1)}-\ln x\right)^{\operatorname {ctg}^{2}(x-1)};

(3)

lim⁡x→1(x−(1/2)ln⁡x)1/(cos⁡2xsin⁡2(1−x))\lim_{x \rightarrow 1}(\sqrt{x}-(1 / 2) \ln x)^{1 /\left(\cos^{2} x \sin^{2}(1-x)\right)}.

Задача 1.19.50

Найти предел.

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(1)

lim⁡x→1(x−ln⁡x)1/(cos⁡2xsin⁡2(1−x))\lim_{x \rightarrow 1}(x-\ln x)^{1 /\left(\cos^{2} x \sin^{2}(1-x)\right)};

(2)

lim⁡x→1(2x−1−xxln⁡2)1/(sin⁡(x−1)−cos⁡(1−x)+x)\lim_{x \rightarrow 1}\left(2^{x-1}-x^{x} \ln 2\right)^{1 /(\sin (x-1)-\cos (1-x)+x)};

(3)

lim⁡x→1+0(ln⁡(x2−x)−ln⁡(x−1)+e1−x)1/arcsin⁡(x−1)3\lim_{x \rightarrow 1+0}\left(\ln \left(x^{2}-x\right)-\ln (x-1)+e^{1-x}\right)^{1 / \arcsin (x-1)^{3}}.

Задача 1.19.51

Найти предел. lim⁡x→1(1ln⁡x−2x2−1)1/sin⁡(x−1)\lim_{x \rightarrow 1}\left(\frac{1}{\ln x}-\frac{2}{x^{2}-1}\right)^{1 / \sin (x-1)}.

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Задача 1.19.52

Найти предел. lim⁡x→1e(x−1)/x−4x−34ch⁡(x−1)−cos⁡2(x−1)\lim_{x \rightarrow 1} \frac{e^{(x-1) / x}-\sqrt[4]{4 x-3}}{\operatorname {ch}(x-1)-\cos 2(x-1)}.

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Задача 1.19.53

Найти предел.

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(1)

lim⁡x→13x3−arcsin⁡(x−1)−3cos⁡(x−1)ex−1−1−ln⁡x\lim_{x \rightarrow 1} \frac{3 \sqrt[3]{x}-\arcsin (x-1)-3 \cos (x-1)}{e^{x-1}-1-\ln x};

(2)

lim⁡x→12x−sin⁡(x−1)−2cos⁡(x−1)arctg⁡(x−1)−ln⁡x\lim_{x \rightarrow 1} \frac{2 \sqrt{x}-\sin (x-1)-2 \cos (x-1)}{\operatorname {arctg}(x-1)-\ln x}.

Задача 1.19.54

Найти предел.

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(1)

lim⁡x→1sin⁡(sin⁡πx)ln⁡(1+ln⁡x)\lim_{x \rightarrow 1} \frac{\sin (\sin \pi x)}{\ln (1+\ln x)};

(2)

lim⁡x→π/21−eπx−2x2cos⁡x\lim_{x \rightarrow \pi / 2} \frac{1-e^{\pi x-2 x^{2}}}{\cos x};

(3)

lim⁡x→π/4ln⁡ctg⁡x+2x−π/2(1−tg⁡x)3\lim_{x \rightarrow \pi / 4} \frac{\ln \operatorname {ctg} x+2 x-\pi / 2}{(1-\operatorname {tg} x)^{3}}.

Задача 1.19.55

Найти предел. lim⁡x→+0x(1−x2)1/2−cos⁡xln⁡(1+x)ln⁡sin⁡x−ln⁡x\lim_{x \rightarrow +0} \frac{x\left(1-x^{2}\right)^{1 / 2}-\cos x \ln (1+x)}{\ln \sin x-\ln x}.

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Задача 1.19.56

Найти предел.

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(1)

lim⁡x→0(1sin⁡x−1tg⁡x)\lim_{x \rightarrow 0}\left(\frac{1}{\sin x}-\frac{1}{\operatorname {tg} x}\right);

(2)

lim⁡x→0(1arctg⁡x−1arcsin⁡x)\lim_{x \rightarrow 0}\left(\frac{1}{\operatorname {arctg} x}-\frac{1}{\arcsin x}\right);

(3)

lim⁡x→0(1x2−1xtg⁡x)\lim_{x \rightarrow 0}\left(\frac{1}{x^{2}}-\frac{1}{x \operatorname {tg} x}\right);

(4)

lim⁡x→0(1(x+1)sh⁡x−ln⁡(1+x)x2)\lim_{x \rightarrow 0}\left(\frac{1}{(x+1) \operatorname {sh} x}-\frac{\ln (1+x)}{x^{2}}\right).

Задача 1.19.57

Найти предел.

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(1)

lim⁡x→∞x(1−xln⁡(1+1/x))\lim_{x \rightarrow \infty } x(1-x \ln (1+1 / x));

(2)

lim⁡x→∞x((2e)1/x+e1/x−2)\lim_{x \rightarrow \infty } x\left((2 e)^{1 / x}+e^{1 / x}-2\right);

(3)

lim⁡x→∞(x3ln⁡(1+1/x)−x2+x/2)\lim_{x \rightarrow \infty }\left(x^{3} \ln (1+1 / x)-x^{2}+x / 2\right).

Задача 1.19.58

Найти предел.

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(1)

lim⁡x→+∞x6+x56+x6−x56−2xxln⁡(1+x)−xln⁡x−xsin⁡(1/x)\lim_{x \rightarrow +\infty } \frac{\sqrt[6]{x^{6}+x^{5}}+\sqrt[6]{x^{6}-x^{5}}-2 x}{x \ln (1+x)-x \ln x-x \sin (1 / x)};

(2)

lim⁡x→+∞x(x2+x−x)+cos⁡xln⁡xln⁡(1+ch⁡x)\lim_{x \rightarrow +\infty } \frac{x\left(\sqrt{x^{2}+x}-x\right)+\cos x \ln x}{\ln (1+\operatorname {ch} x)};

(3)

lim⁡x→+∞x2(x3+x3−x)+sin⁡xln⁡(1+x)ln⁡(1+x+e5x)\lim_{x \rightarrow +\infty } \frac{x^{2}\left(\sqrt[3]{x^{3}+x}-x\right)+\sin x \ln (1+x)}{\ln \left(1+x+e^{5 x}\right)}.

Задача 1.19.59

Найти предел.

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(1)

lim⁡x→+∞(e1/x(x2−x+2)−x4+x2+1)\lim_{x \rightarrow +\infty }\left(e^{1 / x}\left(x^{2}-x+2\right)-\sqrt{x^{4}+x^{2}+1}\right);

(2)

lim⁡x→+∞((x3−x2+x/2+1)e1/x−x12−x9+24)\lim_{x \rightarrow +\infty }\left(\left(x^{3}-x^{2}+x / 2+1\right) e^{1 / x}-\sqrt[4]{x^{12}-x^{9}+2}\right).

Задача 1.19.60

Найти предел.

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(1)

lim⁡x→∞(x5+x45−x5−x45)\lim_{x \rightarrow \infty }\left(\sqrt[5]{x^{5}+x^{4}}-\sqrt[5]{x^{5}-x^{4}}\right);

(2)

lim⁡x→∞((x3+x)sin⁡(1/x)−x6−3x4+13)\lim_{x \rightarrow \infty }\left(\left(x^{3}+x\right) \sin (1 / x)-\sqrt[3]{x^{6}-3 x^{4}+1}\right);

(3)

lim⁡x→∞(x2−x/2−(x3+x+1)ln⁡(1+1/x))\lim_{x \rightarrow \infty }\left(x^{2}-x / 2-\left(x^{3}+x+1\right) \ln (1+1 / x)\right);

(4)

lim⁡x→∞x2+1x(1−x2+1xln⁡x2+x+1x2+1)\lim_{x \rightarrow \infty } \frac{x^{2}+1}{x}\left(1-\frac{x^{2}+1}{x} \ln \frac{x^{2}+x+1}{x^{2}+1}\right).